Webevaluate 301 square - 300 square (use identity) ... evaluate 301 square - 300 square (use identity) 2 comments. share. save. hide. report. 76% Upvoted. This thread is archived. New comments cannot be posted and votes cannot be cast. Sort by: best. level 1 · 8m. I suspect that the identity in question is a 2-b 2 = (a + b)(a - b) WebEvaluate the following by using identities: (97) 2 Medium Solution Verified by Toppr Correct option is A) (97) 2=(100−3) 2 Using identity, (a−b) 2=a 2−2ab−b 2 =(100) 2−2×100×3+(3) 2 =10000−600+9=9409 Was this answer helpful? 0 0 Similar questions Expand the following, using suitable identities: (xy+yz) 2 Medium View solution >

Evaluate (Using Factors) : 3012 X 300 - 3003. - Mathematics

Webusing the identity a 2 − b 2 = ( a + b) ( a − b) First factor out the GCF: 4 ( x 2 − 9 y 4) Both terms are perfect squares so from a 2 - b 2 we can find a and b. a = x 2 = x b = 9 y 4 = 3 y 2 Therefore a 2 − b 2 = ( x) 2 − ( 3 y 2) 2 Complete the factoring of a 2 - b 2 to (a + b) (a - b) 4 ( x + 3 y 2) ( x − 3 y 2) Final Answer: WebSolution The correct option is C 2756 52×53 can be written as (50+2)(50+3) We know that, (x+a)(x+b) =x2+(a+b)x+ab, Here, x=50,a =2 and b =3. ∴ (50+2)(50+3) =(50)2+(2+3)×50+2×3 = 2500+(5×50)+6 = 2500+250+6 = 2756 Suggest Corrections 8 Similar questions Q. Question 86 (viii) Using suitable identities, evaluate the following: 52×53 Q. pottery shepperton

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WebEvaluate 213 × 187 using suitable identity Solution Evaluate Given expression can be written as 213 × 187 = ( 200 + 13) × ( 200 – 13) We know that ( a + b) ( a - b) = a 2 - b 2 … WebApr 2, 2024 · a) 25 b) 35 c)60 d)30 . use Euclid division algorithm to find the HCF of : 135 and 225 . A bag contains some blue, green, red and white balls. one ball is drawn at … Webevaluate 301 square - 300 square (use identity) ... evaluate 301 square - 300 square (use identity) 2 comments. share. save. hide. report. 76% Upvoted. This thread is archived. … tourism in saskatchewan