Tīmeklis2024. gada 18. sept. · You can fix that by adding a process () function to your fizzbuzz.py file: def process(number): if number % 3 == 0: return 'Fizz' This function … Tīmeklis2024. gada 13. apr. · ### FizzBuzz문제 for i in range (1,101): if i%3 ==0: print ( "Fizz", end = "" ) if i%5 ==0: print ( "Buzz", end = "" ) if i%3 !=0 and i%5 !=0 : print (i, end = "" ) print ( "", end = "\\t" ) # 다른 풀이방법 # 빈 문자열은 Flase취급되며, True or True 이면 앞에값만 출력함 # Flas or True 이면 뒤에값만 출력함 for i in range (1,101): print ( …

Почему ваша первая реализация FizzBuzz на Rust может не …

Tīmeklis# This code prints the numbers from 1 to 100, but for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which … TīmeklisHere is the code below for you: a=int (input ('Enter a number: ')) def fizzbuzz (a): if a % 3 == 0: return ('Fizz') elif a % 5 == 0: return ( 'Buzz' ) elif a % 15 == 0: return … spark is a diamond

Fizz Buzz in Python - Medium

TīmeklisFizz-Buzz Program in Python. Fizz-Buzz is the programming task used for explaining the division of numbers in the Fizz, Buzz, and Fizz_Buzz group. Suppose the user … TīmeklisConsider the following problem: Write a short program that prints each number from 1 to 100 on a new line. For each multiple of 3, print "Fizz" instead of the number. For … Tīmeklis1 void printFizzBuzz (int n=100) 2 { 3 for (int i = 1; i <= n; ++i) 4 { 5 if (i % 3 == 0) 6 { 7 if(i % 5 == 0) 8 printf ("FizzBuzz\n"); 9 else 10 printf ("Fizz\n"); 11 } 12 else if (i % 5 == 0) 13 { 14 printf ("Buzz\n"); 15 } 16 else 17 { 18 printf ("%d\n", i); 19 } 20 } 21 } 对于效率问题，这个代码中，每个数进来都只会判断两次并打印出结果。 而对比上面贴出 … tech-con industry