Web16 mrt. 2024 · by an angle 45° about the origin in counterclockwise direction in the first quadrant. Then the area of triangle having vertices (ɑ, β), (0, β) and (0, 0) is equal to: a. 1 b. 1 / 2 c. 1 / √2 d. 2 √2 Answer: (b) (ɑ, β) = (2 cos 75 o, 2 sin 75 o) Area = (1 / 2) (2 cos 75°) (2 sin 75°) = sin (150°) = 1 / 2 square unit WebTrigonometry 4sin2x− 8sinx+3 = 0,t = sinx Similar Problems from Web Search How do you use the quadratic formula to solve 12sin2x− 13sinx +3 = 0 in the interval [0,2π) ? …
If 4 sin2x – 8 sin x + 3 ≤ 0, then the solution set for x ... - BYJUS
Web18 jun. 2024 · => 2 (-2sin^2 (2x) + 1) + 8sin2x - 5 = 0 (dựa vào công thức: cos2a=-2sin^2 (a)+1) => -4sin^2 (2x) + 8sin2x - 3 = 0 => (-4sin^2 (2x) + 2sin2x) + (6sin2x - 3) = 0 => 2sin2x (-2sin2x + 1) - 3 (-2sin2x + 1) = 0 => (2sin2x - 3) (-2sin2x + 1) = 0 => sin2x = 3/2 (loại vì 3/2 > 1) hoặc sin2x = 1/2 (nhận) => sin2x = sinpi/6 WebSolve the inequality 4sin²x+8sinx+3≤0 (4 sinus of squared x plus 8 sinus of x plus 3≤0) - Specify the set of solutions of the inequality in detail step by step. [THERE'S THE … the great outdoors sub shop
Solve for x 8sin(x)^2-4sin(x)=2 Mathway
Webkeep in mind answers should be pi radians or if necessary 3 dec. csc^2-2=0 all angles 4cos^2x-4cosx+1=0 all angles and name 8 angles 7sin^2x-22sinx+3=0 all angles and … WebFind c such that the average value of f is equal to f(c) where f(x)=8sinx -4sin(2x) on the interval [0,pi] I calculated the average value of Avg. satisfaction rating 4.7/5 We are … Web25 okt. 2024 · \(2cos2x + 8sin x -5 = 0 \Leftrightarrow 2(1- 2sin^2x ) +8sinx - 5 = 0\) \(\Leftrightarrow 4sin^2x +8sinx +3 = 0\) \(\Leftrightarrow \bigg \lbrack\begin{matrix} sinx ... the great outdoors subscription